Description
The double.Hypot function returns negative results.
public static double Hypot(double x, double y)
It is in the line result = x + y; where the abs values should be used.
Just as note: I've found that the algorithm used is less precise and slower than a common implementation.
Reproduction Steps
x = double.Hypot(1, +1e20); // 1E+20 ok
x = double.Hypot(1, -1e10); // 1E+10 ok
x = double.Hypot(1, -1e20); // -1E+20 wrong
Expected behavior
x = double.Hypot(1, +1e20); // 1E+20 ok
x = double.Hypot(1, -1e10); // 1E+10 ok
x = double.Hypot(1, -1e20); // 1E+20
Actual behavior
x = double.Hypot(1, +1e20); // 1E+20 ok
x = double.Hypot(1, -1e10); // 1E+10 ok
x = double.Hypot(1, -1e20); // -1E+20 wrong
Regression?
No response
Known Workarounds
No response
Configuration
No response
Other information
No response
Description
The double.Hypot function returns negative results.
public static double Hypot(double x, double y)It is in the line
result = x + y;where the abs values should be used.Just as note: I've found that the algorithm used is less precise and slower than a common implementation.
Reproduction Steps
Expected behavior
Actual behavior
Regression?
No response
Known Workarounds
No response
Configuration
No response
Other information
No response